Copyright 2004 Ken Greenebaum
Exam #3 Dice Info/Entropy
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1 Die
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6 possibilities each with p(e)=1/6
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H(x)=-1/6 log(1/6) - … 1/6 log(1/6)
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= -6*1/6 log(1/6)
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= -log(1/6)
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= 2.587bits
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We know it must be < 3 bits
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since 3 bits can encode 2^3=8 values…